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Title: Boomerang/Science - Unspinning the Boomerang Science article describing the physics of the boomerang.
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Unspinning the boomerangclick here for the plus home page about Plus support Plus subscribe to Plus terms of use search plus with google home latest issue news careers library podcasts browse Plus © 1997-2004, Millennium Mathematics Project, University of Cambridge. Permission is granted to print and copy this page on paper for non-commercial use. For other uses, including electronic redistribution, please contact us. Issue 7January 1999Contents Features Unspinning the boomerang Bang up a boomerang! Galloping gyroscopes Time and motion The origins of proof Career interview Career interview: Games developer Regulars Plus puzzle Editorial Mystery mix Letters Staffroom Introducing the MMP Geometer's corner International Mathematics Enrichment Conference All the latest newsSubscribe to ourfree newsletterSubscribe to the Plus podcast:+iTunesSubscribe to our RSS feed:AddThis Feed Buttonsubscribe to our RSS feedGet your own copy of all the Plus posters! January 1999 Features icon

Unspinning the boomerang

by Hugh Huntaddthis_pub = 'plusmathsorg'; "My boomerang won't come back" goes the song about the disgraced AustralianAborigine. Well, that's not so bad a thing because boomerangs used forhunting kangaroos aren't meant to come back - they are heavy,hockey-stick-shaped throwing sticks that move in a confusingly wobbly path,and they are designed to break the legs or wings of any 'roo or bird theyencounter. So just imagine if that 'rang came back: how would you catchit? It would be as silly as if Robin Hood's deadly arrows came back!The only boomerangs that do come back are those intended to be used as toysand for sport: the Aborigines knew about the fun you can have withboomerangs thousands of years ago. Figure 1: Traditional boomerangs from Australia.Figure 1: Traditional boomerangs from Australia. Perhaps surprisingly, it's reported that the earliest known users of boomerangs were found in what is now Poland, about twenty thousand years ago (18,000 years BC!). Their boomerangs were the traditional bent-stick variety,like the Australian boomerangs in figure 1. It wasn't too hard for boomerangs to bediscovered by accident because if you were stuck for food you might trythrowing a rock, a stick, anything at your prey, and if the stick you founddid funny things you might think it was a magic stick and you'd want to keepit for another throw. Figure 2:  Some modern sports boomerangs.Figure 2: Some modern sports boomerangs.These days, we can make boomerangs in many other curious shapes (figure 2),and some of them fly much better than the traditional ones.In fact, a cross-shaped balsa-wood "boomerang" that looks like a 4-bladedpropellor (figure 3) works really well indoors - inside the average-sized livingroom! We show you how to make one of these in ourBang up a Boomerang! article. Figure 3: Home-made balsa wood boomerangs, suitable for indoor use.Figure 3: Home-made balsa wood boomerangs, suitable for indoor use.

Why do boomerangs fly?

This is the 64,000 Euro question. First let me ask 10 fairly simple (butincreasingly complicated!) related questions. If you can answer all ofthem, then you're well on the way to understanding how a boomerang works: 1. What is (near enough) the shape of the flight path of a boomerang? A. out and back on a straight line; B. circular; C. around the four sides of a square. 2. If I swing a ball on string around my head it follows a circular path;in what direction does the force in the string act? A. downwards; B. always towards the centre of the circle; C. there is no force in the string. 3. An aeroplane wing works because: A. it is an anti-gravity device; B. when it moves through the air at high speed it generates lift; C. it flaps up and down. 4. A helicopter rotor has four blades each in the shape of: A. a feather; B. an airplane wing; C. a circular tube. 5. A cross-shaped boomerang resembles a helicopter rotor because: A. they both have four blades; B. they both generate lift when they spin; C. they work backwards as well as forwards. 6. The lift force of a spinning boomerang is directed mostly: A. downwards; B. towards the centre of its circular flight path; C. there is no lift force. 7. As a spinning boomerang moves forward the uppermost blade moves: A. at the same speed as the centre of the boomerang; B. faster than the centre of the boomerang because it is spinningand moving forwards at the same time; C. downwards. 8. The top of the boomerang generates more lift than the bottom because: A. it is bigger; B. it is moving faster; C. it is heavier. 9. The difference in lift between the top and the bottom of the boomerang: A. doesn't matter; B. forms a couple which causes gyroscopic precession; C. causes the boomerang to bend. 10. Lift on a boomerang causes circular motion and gyroscopic precession: A. which is too complicated for me to understand; B. which balance perfectly - truly a wonderful miracle of nature; C. which the Aborigines could have told you 10,000 years ago.Well, as you might have guessed, the correct answer to all the questions isB. So you have got the idea now that a boomerang works because it spins asit moves forward and the bit of the boomerang that is at the very top movesforward faster than the bit at the bottom so it generates more lift. Figure 4: Flight path of a <b>boomerang.</b>Figure 4: Flight path of a boomerang.Theoverall lift force (like a spinning propellor) points towards the centre ofthe circular flight path which is necessary for circular motion(centripetal acceleration and all that) but the boomerang has to turn toface forwards all the time as it goes around the circle (figure 4 shows the flight path of a boomerang). This isachieved by the difference in lift force between top and bottom . Thisdifference creates a couple, and this couple causes precession. Let's look at this in more detail. Figure 5: A force at a distance producing a couple.Figure 5: A force at a distance producing a couple. What is a couple?A couple is just an "angular force". We all know that to make aroundabout rotate, it is easiest to push on it as far away from thecentre of the roundabout as possible. Our pushing is turned into an"angular force" which turns the roundabout; and the pushing is moreeffective the greater the distance between where we apply the forceand the pivot.A couple therefore has two aspects: a force, and a distance between theline of force and the point of rotation. The magnitude of the couple isgiven by the product of this distance and the size of the force, and thedirection of the couple is at right angles to both. In Figure 5, thecouple C is represented by the red arrow, the point of rotation is thelittle black and white circle marked with a G, and the black arrowxis theposition vector of the point where the force is applied. The definition ofa couple is most succinctly expressed as C = x x F. Any solid body also has an "angular mass", which is properly calledthe moment of inertia of the body. It takes account of how faraway the mass is from the centre of the body: mass which is furtheraway from the point of rotation takes more "angular force" torotate. For example, a roundabout with all the children right at theedge is more difficult to turn than one where all the children areclustered in the middle! Gyroscope designers put as much mass as theycan into the rim of the gyroscope to give them really big moments ofinertia.

The physics of boomerangs

A boomerang does funny things because it is in fact agyroscope. Aerodynamic forces generate a twisting moment which causethe "gyroscope" to precess and to move on a circular path. You can read all about gyroscopes and the physics behind them in this issue's feature article,Galloping gyroscopes.However, to understand what precession is, you simply need to observe that as well as spinning quickly round its own axis, the boomerang slowly changes the direction in which it is pointing (see the flight path illustration of figure 4). You can observe precession yourself if you get an old-fashioned spinning top (yes, they still make them!)and spin it on a smooth surface: as well as spinning about its ownaxis, a well-balanced top should circle around on the surfacebeneath it. Now let’s examine the forces acting on a boomerang of radius $a$. The centre of the boomerang is moving at a constant forward speed $V$ and the boomerang is spinning with angular velocity $\omega $, as shown in the diagram. The "top" end A is therefore moving faster than $V$ with speed $V+a\omega $, and the "bottom" end B is moving slower with speed $V-a\omega $. A wing generates more lift when it is moving faster so point A is generating more lift than point B. The two forces $F_ A$ and $F_ B$ can be represented by a single force $F$ and a single couple $C$. With this simple representation of the forces acting on the boomerang we can give two reasons why it moves on a circular path: A constant centripetal force $F$ produces circular motion with velocity $V$ on a radius $R$ such that \begin{equation}  F = mV^2/R \end{equation}(1) where $m$ is the mass of the boomerang. A constant couple $C$ acting on a gyroscope spinning at angular velocity $\omega $ causes steady precession at rate $\Omega $ such that \begin{equation}  C = J\omega \Omega \end{equation}(2) where $m$ is the mass of the boomerang and $J$ is its moment of inertia. If the rate of precession $\Omega $ exactly corresponds to the angular velocity of circular motion, then the boomerang rotates at exactly the correct rate to stay tangential to the flight path as shown. This gives an equation relating $V$ to $\Omega $, \begin{equation}  V = R\Omega \end{equation}(3)A wing of area $A$ moving at speed $v$ in air with density $\rho $ generates an aerodynamic lift force $L$. It can be shown that $L$ is proportional to the air density, the wing area and the square of the wing speed. The precise relationship is expressed using the proportionality constant $C_ L$, which is known as the lift coefficient, and takes the following form: \begin{equation}  L = \frac{1}{2}\rho v^2C_ LA \end{equation}(4)It can also be shown by integrating the lift force over the area of a cross-shaped boomerang that the net lift force $F$ and aerodynamic couple $C$ are given by \begin{equation}  F = \frac{1}{4}\rho (V^2+(a\omega )^2)C_ LA_ s \end{equation}(5)and \begin{equation}  C = \frac{1}{4}\rho Va^2\omega C_ LA_ s \end{equation}(6)where $V$, $\omega $ and $a$ are the velocity, spin speed and radius of the boomerang as before, and $A_ s = \pi a^2$ (the swept area of the boomerang). From equations 2, 3 and 6, we find that the radius $R$ of the circular flight path is independent of spin speed $\omega $ and forward velocity $V$, and that it is a constant for a given boomerang: \begin{equation}  R = \frac{4J}{\rho C_ L\pi a^4} \end{equation}(7)For the case of a cross-shaped boomerang, $J = \frac{1}{3}ma^2$, and equations 1, 5 and 7 can be arranged to give \begin{equation}  a\omega = \sqrt {2}V \end{equation}(8)which defines the "flick-of-the-wrist" needed to make the boomerang fly properly. loadXMLDoc("/cloud/index/issue7/features/boomerangs/index.html","tags");

About the author

Hugh Hunt showing how a real Aussie throws a boomerang (mind those windows, Hugh!)Hugh Hunt showing how a real Aussie throws a boomerang (mind those windows, Hugh!)Dr. Hugh Hunt is a Lecturer in the Department of Engineering at Cambridge University, and a Fellow of Trinity College, where thisphoto was taken.He hails from Melbourneand has an impressive collection of boomerangs, including one salvagedfrom somebody's kindling pile! You can find out more about boomerangs on hiswebsite. Download PDF version | Printer friendly version Return to article contact copyright info sponsors privacy info mmpnrichmotivate Plus is part of the family of activities in the MillenniumMathematics Project, which also includes the NRICH and MOTIVATE sites. _uacct = "UA-791317-2";urchinTracker();
 

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